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From: whuang@ugcs.caltech.edu (Wei-Hwa Huang)
Subject: Re: Rubiks Revenge moves
Date: 25 Nov 1997 00:44:22 GMT
Organization: California Institute of Technology, Pasadena
Message-Id: <65d716$29p@gap.cco.caltech.edu>
References:
roger.broadie@iclweb.com (Roger Broadie) writes:
>Tenie Remmel wrote (19 November 1997 )
>> Is there an easy way to cycle three adjacent top edges on the
>> Rubiks Revenge? I can't find one shorter than 62 moves, but if
>> there was a short one I could simplify my solution greatly.
>>
>> . b c . . a b .
>> a . . . => c . . .
>> . . . . . . . .
>> . . . . . . . .
>Rather than just throw a few more solutions into the pot, I'd like to start
>with some comments on the sort of process everyone, including me, seems to
>use to deliver 3-cycles of edge pieces in the 4x4x4. It is of the general
>form
> [P, TQT']
>where the square brackets are used to show a commutator, that is, [A,B]
>means ABA'B'.
>In this process P and Q are turns of layers that are parallel to one
>another, and T is a turn of a layer transverse to P and Q.
Count me among the few "self-taught" solvers who don't actually
use this, then. The one I worked out for myself a long time ago
turns out to be:
[r, FUF']
which is of a similar form, but P and Q are not parallel.
As a consequence of this, the permutation is not "clean": i.e.,
some other cubies get disturbed. As these are all face cubies
anyway, I just modified my solution so that I do the face cubies
last. :-)
--
Wei-Hwa Huang, whuang@ugcs.caltech.edu, http://www.ugcs.caltech.edu/~whuang/
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