From cube-lovers-errors@mc.lcs.mit.edu Mon Nov 24 21:00:19 1997 Return-Path: Received: from sun30.aic.nrl.navy.mil by mc.lcs.mit.edu (8.8.1/mc) with SMTP id VAA05989; Mon, 24 Nov 1997 21:00:19 -0500 (EST) Precedence: bulk Errors-To: cube-lovers-errors@mc.lcs.mit.edu Mail-from: From cube-lovers-request@life.ai.mit.edu Mon Nov 24 19:45:36 1997 To: Cube-Lovers@AI.MIT.Edu From: whuang@ugcs.caltech.edu (Wei-Hwa Huang) Subject: Re: Rubiks Revenge moves Date: 25 Nov 1997 00:44:22 GMT Organization: California Institute of Technology, Pasadena Message-Id: <65d716$29p@gap.cco.caltech.edu> References: roger.broadie@iclweb.com (Roger Broadie) writes: >Tenie Remmel wrote (19 November 1997 ) >> Is there an easy way to cycle three adjacent top edges on the >> Rubiks Revenge? I can't find one shorter than 62 moves, but if >> there was a short one I could simplify my solution greatly. >> >> . b c . . a b . >> a . . . => c . . . >> . . . . . . . . >> . . . . . . . . >Rather than just throw a few more solutions into the pot, I'd like to start >with some comments on the sort of process everyone, including me, seems to >use to deliver 3-cycles of edge pieces in the 4x4x4. It is of the general >form > [P, TQT'] >where the square brackets are used to show a commutator, that is, [A,B] >means ABA'B'. >In this process P and Q are turns of layers that are parallel to one >another, and T is a turn of a layer transverse to P and Q. Count me among the few "self-taught" solvers who don't actually use this, then. The one I worked out for myself a long time ago turns out to be: [r, FUF'] which is of a similar form, but P and Q are not parallel. As a consequence of this, the permutation is not "clean": i.e., some other cubies get disturbed. As these are all face cubies anyway, I just modified my solution so that I do the face cubies last. :-) -- Wei-Hwa Huang, whuang@ugcs.caltech.edu, http://www.ugcs.caltech.edu/~whuang/ --------------------------------------------------------------------------- "[Lucy's eyes] look like little round dots of India ink..." -- Charlie Brown