From Mikko.Haapanen@otol.fi Thu Jan 13 09:19:35 1994 Return-Path: Received: from lassie.eunet.fi by life.ai.mit.edu (4.1/AI-4.10) for /com/archive/cube-lovers id AA02187; Thu, 13 Jan 94 09:19:35 EST Received: from sulo.otol.fi by lassie.eunet.fi with SMTP id AA29207 (5.67a/IDA-1.5 for ); Thu, 13 Jan 1994 16:19:16 +0200 Received: from rhea.otol.fi by sulo.otol.fi with SMTP (PP) id <01542-0@sulo.otol.fi>; Thu, 13 Jan 1994 16:19:11 +0200 Received: from otol.fi by rhea.otol.fi id <26762-0@rhea.otol.fi>; Thu, 13 Jan 1994 16:19:00 +0200 Date: Thu, 13 Jan 1994 16:17:01 +0200 (EET) From: "M. Haapanen" Sender: "M. Haapanen" Reply-To: "M. Haapanen" Subject: Re: 4x4x4 Cube moves To: cube-lovers@life.ai.mit.edu In-Reply-To: <60.694.5834.0C190EF0@canrem.com> Message-Id: Mime-Version: 1.0 Content-Type: TEXT/PLAIN; CHARSET=US-ASCII > ... > This is the shortest sequence I found for flipping 2 adjacent > edges on the 4x4x4 cube (LD pair): > > (r3 D3) ^3 + (r1 D1) ^4 + Rr3 D3 R1 D1 r3 D3 R3 D1 R1 D3 > > Note the use of Rr to represent both the turns R face & r inner > slice. Counting slice turns the sequence is 25 turns, or > 24 "hyper moves". This sequence moves some centre pieces around. > > However, on checking David Singmaster's Cubic Circular, in issues > 5 & 6, Autumn & Winter 1982 there is a shorter process on > page 15, (UB pair): > > r2 D2 l3 D1 R3 U1 R3 U3 l3 U1 R1 U3 l1 R1 D1 r2 > > This process, although more difficult to memorize, is only 16 slice > moves. It also disturbs centre pieces, although in a simpler way. > I always solve the centre pieces last on the 4x4x4. Thank you. But what is the shortest way to flip 2 adj. edges without messing the center pieces? I can't find shorter than 49 turns. -=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=- -= Mikko Haapanen -=-=- hazard57@sulo.otol.fi -=-=- (981) 530 7768 =- -=-=-=-=-=-=-=-=-=-= Haapanatie 2C411 90150 OULU =-=-=-=-=-=-=-=-=-=-